192.168.16.185 This is a Class C IP address
The default mask is 255.255.255.0
To create minimum 10 subnets we need to borrow 4 host bits.
If you borrow 4 host bits the new subnet mask will be
255.255.255.240 and the network increment is 16
Therefore the first subnet would be 192.168.16.0
The second subnet would be 192.168.16.16
The third subnet would be 192.168.16.32
The 10th subnet would be 192.168.16.160
The first host IP address in 10th subnet would be 192.168.16.161
Tha last valid IP address in 10 subnet is 192.168.16.174
The broadcast address of the 10 subnet would be 192.168.16.175
Your answer should be 192.168.16.161 255.255.255.240
If you didnt get this dont worry , I had the same problem.
Have a look at this document. This helped me a lot to understand subnetting.
There are good websites to practice subnetting.
Yes, my calculations agree with yours.
192.168.16.176 is The subnet (12th BTW) First host 192.168.16.177, last host 192.168.16.190. Broadcast 192.168.16.191
BTW I calculated this manually and checked my work using the "Solarwinds Advance Subnet Calculator" a great free tool. It does NOT generate questions, but sure helps in verifying your answers
Good Evening Kapila,
I've had time to go over your explanation to my question and am very grateful for you help so far but I'm just a little confused about one thing, please see the below:
Q: You will need to apply an IP address to the
interface based on the below information after enabling RIP version 2:
Fa0 IP 192.168.16.185 using the tenth subnet
192.168.16.185 - Class C address
255.255.255.0 - Default Mask
Borrow 4 host bits which give the new subnet mask: 255.255.255.240 with an increment of 16
1st Subnet: 192.168.16.0
2nd Subnet: 192.168.16.16
3rd Subnet: 192.168.16.32
4th Subnet: 192.168.16.48
5th Subnet: 192.168.16.64
6th Subnet: 192.168.16.80
7th Subnet: 192.168.16.96
8th Subnet: 192.168.16.112
9th Subnet: 192.168.16.128
10th Subnet: 192.168.16.144
11th Subnet: 192.168.16.160
I thought we count "0" as being the first subnet? or am missing something? Just would like to understand this question.
Shouldn't my answer be: 192.168.16.145 255.255.255.240
Please can you advise?