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This Question is Answered 1 Helpful Answer available (2 pts)
5529 Views 6 Replies Latest reply: Oct 2, 2008 10:09 PM by Lee Phillips RSS

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IP Subnetting Format

Oct 1, 2008 2:19 AM

Lee Phillips 19 posts since
Jul 25, 2008

 

 

 

 

Hi,

 

 

 

 

 

I have recently failed an exam and would greatly appreciate some feedback in regards to the below question. I’m going to structure this question as clearly as I can but please keep in mind that it may not be correct as I didn’t understand it myself, hence the reason for putting my query here.

 

 

 

 

 

Q: You will need to apply an IP address to the interface based on the below information after enabling RIP version 2:

 

 

 

 

 

Fa0 IP 192.168.16.185 using the tenth subnet

 

 



 

 

As it may be quite clear on how to obtain the answer here, I was confused during the exam as I’m use to subnetting questions structured in this format 192.168.16.185 255.255.255.x or 192.168.16.185/2x

 

 

 

 

 

This may be a question for the Cisco admin/management team to advise me but anyone feel free to share? Furthermore does anyone know where there is a website where I could get examples on how to understand this nature of questions?

 

 

 

 

 

Kind Regards

 

 

 

 

 

Lee Phillips

 

 

  • Kapila Withanawasam 3 posts since
    Jul 4, 2008
    Currently Being Moderated
    1. Oct 1, 2008 5:27 AM (in response to Lee Phillips)
    Re: IP Subnetting Format

    Hi Lee,

     

    192.168.16.185 This is a Class C IP address

     

     

    The default mask is 255.255.255.0

     

     

    To create minimum 10 subnets we need to borrow 4 host bits.

     

     

    If you borrow 4 host bits the new subnet mask will be

     

     

    255.255.255.240 and the network increment is 16

     

     

    Therefore the first subnet would be 192.168.16.0

     

     

    The second subnet would be 192.168.16.16

     

     

    The third subnet would be 192.168.16.32

     

     

    The 10th subnet would be 192.168.16.160

     

     

    The first host IP address in 10th subnet would be 192.168.16.161

     

     

    Tha last valid IP address in 10 subnet is 192.168.16.174

     

     

    The broadcast address of the 10 subnet would be 192.168.16.175

     

     

    Your answer should be 192.168.16.161 255.255.255.240

     

     

    If you didnt get this dont worry , I had the same problem.

     

     

    Have a look at this document. This helped me a lot to understand subnetting.

     

     

    There are good websites to practice subnetting.

     

     

    Regards,

     

     

    Kapila

     

     

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  • Bert-Jan Vosman 3 posts since
    Aug 3, 2008
    Currently Being Moderated
    2. Oct 1, 2008 1:28 PM (in response to Lee Phillips)
    Re: IP Subnetting Format

     

    ip address 192.168.16.185 /28

     

     

    is on subnet 192.168.16.176

     

     

    first available ip address would be 192.168.16.177

     

     

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  • cnewby 75 posts since
    Apr 21, 2008
    Currently Being Moderated
    3. Oct 1, 2008 4:50 PM (in response to Bert-Jan Vosman)
    Re: IP Subnetting Format

    Hi Bert-Jan,

     

    Yes, my calculations agree with yours.

     

     

     

    192.168.16.176 is The subnet (12th BTW) First host 192.168.16.177, last host 192.168.16.190. Broadcast 192.168.16.191

     

     

     

    BTW I calculated this manually and checked my work using the "Solarwinds Advance Subnet Calculator" a great free tool. It does NOT generate questions, but sure helps in verifying your answers

     

     

     

    Charles

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  • Kapila Withanawasam 3 posts since
    Jul 4, 2008
    Currently Being Moderated
    5. Oct 2, 2008 10:03 PM (in response to Lee Phillips)
    Re: IP Subnetting Format

     

    Hi Lee,

     

     

    You are correct, the 10th subnet is 192.168.16.144

     

     

    It is my mistake.

     

     

    Kapila

     

     

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