when u r using ip default-network or ip route 0.0.0.0 0.0.0.0 command means u r injecting a default route in the network. So to do so u have inject a route whose subnet mask is default in all the networks. So ip default-network uses classful addressing scheme. the subnet mask of the default route must be same in all the networks......
I did a lab today and wanted to share the results and correct answers (gathered from others) here:
There are 4 methods of creating a default candidate route in EIGRP:
- 'ip route 0.0.0.0 0.0.0.0' + 'network 0.0.0.0'
- 'ip summary-address eigrp X 0.0.0.0 0.0.0.0' + 'network 0.0.0.0'
- 'ip route 0.0.0.0 0.0.0.0' + 'network x.x.x.x' + 'redistribute static' <- create an external route
- 'ip address n.n.n.n' + 'ip default-gateway n.n.n.n' <- additional routes may needed to indicate further subnets
Every single method create a default candidate route.
There is no default route, the correct term is default candidate.
this is an old post but I'm hoping that you're still monitoring this account. I'm studying the ccnp route as well and I'm asking myself the exact same questions as you did.
So just to be clear there's no such thing as 100% default route right? No matter what method we use it's going to make that route a default *canditate* meaning that if there's a better candidate it will be replaced with that. It doesn't mean that one method goes straight into the routing table as gateway of last resort without first considering the other candidates... all these methods will always create a candidate.. is that right?
thank you for your great post